COUNT + DISTINCT
SELECT COUNT(aid) FROM au;
+------------+
| COUNT(aid) |
+------------+
| 669 |
+------------+SELECT COUNT(DISTINCT aid) FROM au;
+---------------------+
| COUNT(DISTINCT aid) |
+---------------------+
| 515 |
+---------------------+SELECT COUNT(DISTINCT column_name) AS unique_count
FROM table_name;SELECT COUNT(DISTINCT department) AS unique_departments
FROM employees;Last updated